Length of an Archimedean Spiral
[21 Sep 2011]
Reader Anantha recently wrote asking the following interesting question:
To find the total length of a flat spiral having outer end radius = 15.5 units, inner radius = 5 units & the increase in radius per turn = 0.81 unit, the total No. of turns in the spiral is 7.5.
This is an example of an Archimedean Spiral, otherwise known as an arithmetic spiral, where the arms get bigger by a constant amount for each turn.
We can see Archimedean Spirals in the spring mechanism of clocks and in vinyl records (used by the recording industry before CDs and MP3s); and in tightly coiled rope.
Watch mechanism [Image source]
Coiled rope [Image source]
However, her question can’t be solved
This was another example of an impossible-to-solve reader question. (Some of them are not possible to solve either because there is not enough information given, the algebra is unreadable, or some key vocabulary is not used correctly.)
In this case, it’s not possible because it has a fundamental flaw.
If the inner radius is 5 units and the increase in radius per turn is 0.81 units, then 7.5 turns will give us an outer radius of:
5 + 0.81 × 7.5 = 11.075
So the outer radius cannot be 15.5 units if the increase per turn is 0.81.
Here’s what the spiral with 0.81 radius increase per turn looks like:
Archimedean spiral, 0.81 units between each arm;
outer radius is 11.075
On the other hand, if is it important to have the outer radius being 15.5 units, then the increase per turn would need to be:
(15.5 − 5)/7.5 = 10.5/7.5 = 1.4
Here’s the spiral with inner radius 5, outer radius 15.5 after 7.5 turns:
Archimedean spiral, inner radius 5, outer radius 15.5;
distance between each arm is 1.4 units
The increase per turn is 1.4 units.
Finding the Length of the Spiral
Before we can find the length of the spiral, we need to know its equation.
An Archimedean Spiral has general equation in polar coordinates:
r = a + bθ,
where r is the distance from the origin, a is the start point of the spiral and b affects the distance between each arm. (The total angle turned by the spiral in radians is given by 2πb, so the distance between each arm is 2πb divided by the number of turns.)
For both spirals given above, a= 5, since the curve starts at 5.
For the first spiral,
2πb = 0.81, giving us b = 0.12892
So the formula for the first spiral is
r = 5 + 0.12892θ
Using the same process, the formula for the second spiral is:
r = 5 + 0.22282θ
Length of the first spiral
We’ll use the formula for the Arc Length of a Curve in Polar Coordinates to find the length.
The starting value for θ is a = 0 and after 7.5 turns, the end point is b = 7.5 × 2π = 15π = 47.12389.
The derivative under the square root is straightforward:
Substituting everything into our formula gives us:
You can see where that final answer comes from in Wolfram|Alpha. It may be possible to find the actual integral on paper (it involves hyperbolic functions), but why waste our lives doing so? We are interested in the length, not pages of algebra!
Length of the second spiral
I’ve solved the second one as an example in the section Arc Length of a Curve in Polar Coordinates.
So Anantha, I hope that helps to answer your question.