# Finding the Area with Pythagoras's theorem [Solved!]

**Joanne** 23 May 2020, 12:27

### My question

the length of the longer side of a parallelogram is twice the length of the shorter side and two of the internal angles are 60 degrees. the length of the shorter diagonal is 3 cm. what is the area of the parallelogram?

### Relevant page

3. Values of Trigonometric Functions

### What I've done so far

I haven't done anything yet as I am unable to find the height of the parallelogram.

X

the length of the longer side of a parallelogram is twice the length of the shorter side and two of the internal angles are 60 degrees. the length of the shorter diagonal is 3 cm. what is the area of the parallelogram?

Relevant page
<a href="/trigonometric-functions/3-values-trigonometric-functions.php">3. Values of Trigonometric Functions</a>
What I've done so far
I haven't done anything yet as I am unable to find the height of the parallelogram.

## Re: Finding the Area with Pythagoras's theorem

**Murray** 23 May 2020, 23:08

In the "relevant page" in your question, you'll see a discussion about 30-60 triangle. That should help get you started.

X

In the "relevant page" in your question, you'll see a discussion about 30-60 triangle. That should help get you started.

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