phinah 08 Apr 2019, 15:31
On your site, the Plane Analytical Geometry Chapter, section 3 - The Circle, at the end of exercise 3 there is the "EXERCISE FOR YOU."
You post that the radius is 1.63. How did you arrive at that number? I come up with 1.58.
I completed the square thereby adding `9/4` and `1/4` to the right side of the equation. So `r^2 = 10/4,` or `2.5.` So `r,` the square root of `2.5,` is `1.58.`
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On your site, the Plane Analytical Geometry Chapter, section 3 - The Circle, at the end of exercise 3 there is the "EXERCISE FOR YOU." You post that the radius is 1.63. How did you arrive at that number? I come up with 1.58.
Relevant page <a href="https://www.intmath.com/plane-analytic-geometry/3-circle.php">3. The Circle</a> What I've done so far I completed the square thereby adding `9/4` and `1/4` to the right side of the equation. So `r^2 = 10/4,` or `2.5.` So `r,` the square root of `2.5,` is `1.58.`
Murray 09 Apr 2019, 22:21
@phinah: Indeed, you are correct. It was a typo on my part. (The radius of the circle in the image is correct at `sqrt(2.5),` but my image caption was not.)
I've fixed the issue.
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@phinah: Indeed, you are correct. It was a typo on my part. (The radius of the circle in the image is correct at `sqrt(2.5),` but my image caption was not.) I've fixed the issue.
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