We complete the square as we did in an earlier example above.
First, we collect the x parts together and the y parts together, then divide throughout by 3.
Then we complete the square on the x part. We do not need to do so for the y part because there is no single y term (only a y2 term).
So the circle has centre `(2,0)` and has radius `sqrt(8/3)~~1.63`.
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