2. Area Under a Curve

by M. Bourne

We met areas under curves earlier in the Integration section (see 3. Area Under A Curve), but here we develop the concept further. (You may also be interested in Archimedes and the area of a parabolic segment, where we learn that Archimedes understood the ideas behind calculus, 2000 years before Newton and Leibniz did!)

It is important to sketch the situation before you start.

We wish to find the area under the curve `y = f(x)` from `x = a` to `x = b`.

We can have several situations:

Case 1: Curves which are entirely above the x-axis.

Area under a curve - vertical rectangles

In this case, we find the area by simply finding the integral:

`"Area"=int_a^bf(x)dx`

Where did this formula come from?

Area Under a Curve from First Principles

In the diagram above, a "typical rectangle" is shown with width `Δx` and height `y`. Its area is `yΔx`.

If we add all these typical rectangles, starting from `a` and finishing at `b`, the area is approximately:

`sum_{x=a}^\b(y)Deltax`

Now if we let `Δx → 0`, we can find the exact area by integration:

`"Area"=int_a^bf(x)dx`

This follows from the Riemann Sums, from the Introduction to Integration chapter.

Example of Case 1

Need Graph Paper?

rectangular grid
Download graph paper

Find the area underneath the curve `y = x^2+ 2` from `x = 1` to `x = 2`.

Case 2: Curves which are entirely below the x-axis

We consider the case where the curve is below the `x`-axis for the range of `x` values being considered.

Area under curve - below x-axis

In this case, the integral gives a negative number. We need to take the absolute value of this to find our area:

`"Area"=|int_a^bf(x)dx|`

Example of Case 2

Find the area bounded by `y = x^2 − 4`, the `x`-axis and the lines `x = -1` and `x = 2`.

Case 3: Part of the curve is below the x-axis, part of it is above the x-axis

Area under curve - crossing x-axis

In this case, we have to sum the individual parts, taking the absolute value for the section where the curve is below the `x`-axis (from `x = a` to `x = c`).

`"Area"=|int_a^cf(x)dx|+int_c^bf(x)dx`

If we don't do it like this, the "negative" area (the part below the `x`-axis) will be subtracted from the "positive" part, and our total area will not be correct.

Example of Case 3

What is the area bounded by the curve `y = x^3`, `x = -2` and `x = 1`?

Summary (so far)

In each of Case 1, Case 2 and Case 3, we are summing elements left to right, like this:

Area under curve - vertical rectangles

We are (effectively) finding the area by horizontally adding the areas of the rectangles, width `dx` and heights `y` (which we find by substituting values of `x` into `f(x)`).

So

`A=int_a^bf(x)dx`

(with absolute value signs where necessary, if the curve goes under the `x`-axis).

Case 4: Finding areas by summing vertically

In some cases, it is easier to find the area if we take vertical sums. Sometimes the only possible way is to sum vertically.

Area under curve - horizontal rectangles

In this case, we find the area is the sum of the rectangles, heights `x = f(y)` and width `dy`.

If we are given `y = f(x)`, then we need to re-express this as `x = f(y)` and we need to sum from bottom to top.

So, in case 4 we have:

`A=int_c^df(y)dy`

Example of Case 4

Find the area of the region bounded by the curve `y=sqrt(x-1)`, the `y`-axis and the lines `y = 1` and `y = 5`.

Didn't find what you are looking for on this page? Try search:

Online Algebra Solver

This algebra solver can solve a wide range of math problems. (Please be patient while it loads.)

Ready for a break?

 

Play a math game.

(Well, not really a math game, but each game was made using math...)

The IntMath Newsletter

Sign up for the free IntMath Newsletter. Get math study tips, information, news and updates each fortnight. Join thousands of satisfied students, teachers and parents!

Given name: * required

Family name:

email: * required

See the Interactive Mathematics spam guarantee.

Share IntMath!

Calculus Lessons on DVD

 

Easy to understand calculus lessons on DVD. See samples before you commit.

More info: Calculus videos

Loading...
Loading...