We sketch the upper and lower bounding curves:

cup

The lower limit of integration is x = 0 (since the question says x ≥ 0).

Next, we need to find where the curves intersect so we know the upper limit of integration.

Equating the 2 expressions and solving:

2x2 = x + 1

2x2x − 1 = 0

(2x + 1)(x − 1) = 0

x = 1 (since we only need to consider x ≥ 0. This is consistent with what we see in the graph above.)

So with y2 = x + 1 and y1 = 2x2, the volume required is given by:

cup 3

Here is an indication of the volume we have found. A typical "washer" with outer radius y2 = x + 1 and inner radius y1 = 2x2 is shown.

cup graph