6. Moments of Inertia

by M. Bourne

The moment of inertia is a measure of the resistance of a rotating body to a change in motion.

The moment of inertia of a particle of mass m rotating about a particular point is given by:

Moment of inertia = md2

where d is the radius of rotation.

Inertia for a Collection of Particles

If a group of particles with masses m1, m2, m3, ... , mn is rotating around a point with distances d1, d2, d3, ... dn, (respectively) from the point, then the moment of inertia I is given by:

I = m1d12 + m2d22 + m3d32 ... + mndn2

If we wish to place all the masses at the one point (R units from the point of rotation) then

d1 = d2 = d3 = ... = dn = R and we can write:

I = (m1 + m2 + m3 ... + mn)R2

R is called the radius of gyration.

 

Example:

Find the moment of inertia and the radius of gyration w.r.t. the origin (0,0) of a system which has masses at the points given:

Mass 6 5 9 2
Point (-3,0) (-2,0) (1,0) (8,0)
Answer

 

 

Moment of Inertia for Areas

area between curves


We want to find the moment of inertia, Iy of the given area, which is rotating around the y-axis.

Each "typical" rectangle indicated has width dx and height y2y1, so its area is (y2y1)dx.

If k is the mass per unit area, then each typical rectangle has mass k(y2y1)dx.

The moment of inertia for each typical rectangle is [k(y2y1)dx] x2, since each rectangle is x units from the y-axis.

We can add the moments of inertia for all the typical rectangles making up the area using integration:

math image

Using a similar process that we used for the collection of particles above, the radius of gyration Ry is given by:

math image

where m is the mass of the area.

 

Example:

For the first quadrant area bounded by the curve

y = 1 − x2,

find:

a) The moment of inertia w.r.t the y axis. (Iy)

b) The mass of the area

c) Hence, find the radius of gyration

Answer

 


Note: For rotation about the x-axis, the formulae become:

math image

and

math image




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