vectors - 3D box example

Using the formula

A × B = |A| |B| sin θ n

and our values from before which were

|BS| = √3
|CP| = √3
θ = 70.5°

we have:

|BS| × |CP|

= |BS| |CP| sin θ n

= (√3)(√3) sin 70.5° n

= 2.828 n

This means our result is a vector with magnitude `2.828` units and direction perpendicular to the plane containing BS and CP, indicated in green in the following diagram.

final - cross product demonstration

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