# Line slope calculator 2x-4y=-28

**Straight line given by points A[2; 8] and B[6; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.5x+7

**Canonical form of the line equation:**2x-4y+28 = 0

**Parametric form of the line equation:**

x = 4t+2

y = 2t+8 ; t ∈ R

**Slope:**m = 0.5

**Slope angle of line: φ =**26°33'54″ = 0.4636 rad

**X intercept:**x

_{0}= -14

**Y intercept:**y

_{0}= q = 7

**Distance line from the origin:**d

_{0}= 6.261

**The length of the segment AB: |AB| =**4.4721

**Vector: AB =**(4; 2)

**Normal vector: n =**(2; -4)

**Midpoint of the segment AB: M =**[4; 9]

**Perpendicular Bisector equation:**4x+2y-34 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (6; 10) ; |OB| = 11.6619**

**Scalar product OA .OB = 92**

**Angle ∠ AOB = 16°55'39″ = 0.2954 rad**