This time, *x*_{1} = 3 and *y*_{1} =
−1; *x*_{2} = −2 and *y*_{2} = 5

So the distance is given by:

`d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

`=sqrt((-2-3)^2+(5-(-1))^2)`

`=sqrt(25+36)`

`=sqrt61`

`=7.8102`

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