We will have vertex at (-1,2) and p = -3 (so the parabola will be "upside down").
The vertex is at (-1, 2), since we know the focal distance is | p | = 3.
We don't really need to find the equation, but as an exercise:
Using
(x − h)2 = 4p(y − k)
We have:
(x + 1)2 = 4(-3)(y − 2)
x2 + 2x + 1 = -12y + 24
12y = -x2 − 2x − 1 + 24
y = (-x2 − 2x + 23)/12