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Laplace Transform for Step function [Solved!]

My question

How to find the Laplace transform of Heaviside function multiplied by derivative?
(dp/dt)*(1-U(t-a)).
dp/dt =Pressure derivative with respect to time.
a= constant.
U= is the step function.

Relevant page

1a. The Unit Step Function - Definition

What I've done so far

(dp/dt)(1-U(t-a))

X

How to find the Laplace transform of Heaviside function multiplied by derivative?
(dp/dt)*(1-U(t-a)).
dp/dt =Pressure derivative with respect to time.
a= constant.
U= is the step function.
Relevant page

<a href="/laplace-transformation/1a-unit-step-functions-definition.php">1a. The Unit Step Function - Definition</a>

What I've done so far

(dp/dt)(1-U(t-a))

Re: Laplace Transform for Step function

@eitaleb: The derivative of a unit step function is an impulse function:

Derivative of unit step function

You'll find a section on finding the Laplace of it on this page:

Laplace Transform of Functions

X

@eitaleb: The derivative of a unit step function is an impulse function:

<a href="https://math.stackexchange.com/questions/1993827/derivative-of-unit-step-function">Derivative of unit step function</a>

You'll find a section on finding the Laplace of it on this page:

<a href="https://lpsa.swarthmore.edu/LaplaceXform/FwdLaplace/LaplaceFuncs.html">Laplace Transform of Functions</a>

Re: Laplace Transform for Step function

I don’t need the derivation of step function.
What I have is derivative of pressure with respect to time multiplied by Step function. I want the Laplace of the whole term.
L { f’(t) * (1-U(t-2))}

X

I don’t need the derivation of step function. 
What I have is derivative of pressure with respect to time multiplied by Step function. I want the Laplace of the whole term.
L { f’(t) * (1-U(t-2))}

Re: Laplace Transform for Step function

Ah, I see. Sorry, didn't read it carefully.

Anyone else like to chime in here?

X

Ah, I see. Sorry, didn't read it carefully.

Anyone else like to chime in here?

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