# Hyperbolic functions [Solved!]

**Matt** 25 Nov 2015, 09:42

### My question

Hi,

I have this problem to solve:

1 + (e2A-e-2A/2) + (e2A+e-2A/2)

----------------------------------

1 - (e2A-e-2A/2) - (e2A+e-2A/2)

The (2A) is are the the power of (e)

Can you help me simplify this please?

Thanks

Matt

### Relevant page

Analytic Trigonometry

### What I've done so far

Expanded it out and tried to simplfy, but couldnt do it

X

Hi,
I have this problem to solve:
1 + (e2A-e-2A/2) + (e2A+e-2A/2)
----------------------------------
1 - (e2A-e-2A/2) - (e2A+e-2A/2)
The (2A) is are the the power of (e)
Can you help me simplify this please?
Thanks
Matt

Relevant page
<a href="/analytic-trigonometry/analytic-trigo-intro.php">Analytic Trigonometry</a>
What I've done so far
Expanded it out and tried to simplfy, but couldnt do it

## Re: Hyperbolic functions

**Murray** 26 Nov 2015, 02:59

Hello Matt

I suspect your brackets are in the wrong place. (The "/2" should be outside the bracket, yes?)

I don't have hyperbolic functions on IntMath (yet). You can go to this page for more information:

Hyperbolic function

I suggest that you write out carefully the top and bottom of your fraction and you will see some things disappear. Then try to recognise what you have got in the "Standard Algebraic Expressions" on that Wikipedia site. It's one of the expressions listed there.

I also suggest you use the math entry system so it's easier for you - and us - to read your math.

I hope that helps. There is not much to do in this problem - just simplify and then recognise.

Regards

X

Hello Matt
I suspect your brackets are in the wrong place. (The "/2" should be outside the bracket, yes?)
I don't have hyperbolic functions on IntMath (yet). You can go to this page for more information:
<a href="https://en.wikipedia.org/wiki/Hyperbolic_trigonometric_function">Hyperbolic function</a>
I suggest that you write out carefully the top and bottom of your fraction and you will see some things disappear. Then try to recognise what you have got in the "Standard Algebraic Expressions" on that Wikipedia site. It's one of the expressions listed there.
I also suggest you use the math entry system so it's easier for you - and us - to read your math.
I hope that helps. There is not much to do in this problem - just simplify and then recognise.
Regards

## Re: Hyperbolic functions

**Matt** 26 Nov 2015, 16:30

Yah, it's better using the math writing system.

This was the question (you're right, I was missing some brackets):

`(1 + (e^(2A)-e^(-2A)/2) + (e^(2A)+e^(-2A)/2)) / (1 - (e^(2A)-e^(-2A)/2) - (e^(2A)+e^(-2A)/2))`

I still don't know what to do next.

X

Yah, it's better using the math writing system.
This was the question (you're right, I was missing some brackets):
`(1 + (e^(2A)-e^(-2A)/2) + (e^(2A)+e^(-2A)/2)) / (1 - (e^(2A)-e^(-2A)/2) - (e^(2A)+e^(-2A)/2))`
I still don't know what to do next.

## Re: Hyperbolic functions

**Murray** 27 Nov 2015, 02:45

Are you sure you've got the right expression?

I suspect you are still missing some brackets there!

X

Are you sure you've got the right expression?
I suspect you are still missing some brackets there!

## Re: Hyperbolic functions

**Matt** 27 Nov 2015, 12:03

`(1 + (e^(2A)-e^(-2A))/2 + (e^(2A)+e^(-2A))/2) / (1 - (e^(2A)-e^(-2A))/2 - (e^(2A)+e^(-2A))/2)`

That looks better! What do I do now?

X

`(1 + (e^(2A)-e^(-2A))/2 + (e^(2A)+e^(-2A))/2) / (1 - (e^(2A)-e^(-2A))/2 - (e^(2A)+e^(-2A))/2)`
That looks better! What do I do now?

## Re: Hyperbolic functions

**Murray** 27 Nov 2015, 23:10

Now that I've seen your actual question, it rings a bell. It's the same as this forum question:

Trigonometry equation

Hope it helps.

X

Now that I've seen your actual question, it rings a bell. It's the same as this forum question:
<a href="http://www.intmath.com/forum/analytic-trigonometry-25/trigonometry-equation:16">Trigonometry equation</a>
Hope it helps.

## Re: Hyperbolic functions

**Matt** 28 Nov 2015, 17:42

It did. I appreciate your help.

X

It did. I appreciate your help.

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