Perpendicular Distance from a Point to a Line
(BTW - we don't really need to say 'perpendicular' because the distance from a point to a line always means the shortest distance.)
This is a great problem because it uses all these things that we have learned so far:
- distance formula
- slope of parallel and perpendicular lines
- rectangular coordinates
- different forms of the straight line
- solving simultaneous equations
The distance from a point (m, n) to the line Ax + By + C = 0 is given by:
There are some examples using this formula following the proof.
Proof of the Perpendicular Distance Formula
Let's start with the line Ax + By + C = 0 and label it DE. It has slope
.

We have a point P with coordinates (m, n). We wish to find the perpendicular distance from the point P to the line (that is, distance PQ).

We now do a trick to make things easier for ourselves (the algebra is really horrible otherwise). We construct a line parallel to DE through (m, n). This line will also have slope
, since it is parallel to DE. We will call this line FG.

Now we construct another line parallel to PQ passing through the origin.
This line will have slope
, because it is perpendicular to DE.
Let's call it line RS. We extend it to the origin (0, 0).
We will find the distance RS, which I hope you agree is equal to the distance PQ that we wanted at the start.

Since FG passes through (m, n) and has slope
, its equation is
or
.
Line RS has equation ![]()
Line FG intersects with line RS when
Solving this gives us
So after substituting this back into
, we find that point R is
Point S is the intersection of the lines
and Ax + By + C = 0
(which can be written
).
This occurs when (that is, we are solving them simultaneously)
Solving for x gives
Finding y by substituting back into
gives
So S is the point
So the distance RS, using the distance formula,
is

The absolute value sign is necessary since distance must be a positive value, and certain combinations of A, m , B, n and C can produce a negative number in the numerator.
So the distance from the point (m, n) to the line Ax + By + C = 0 is given by:
Example 1
Find the perpendicular distance from the point (5, 6) to the line -2x + 3y + 4 = 0, using the formula we just found.
Example 2
Find the distance from the point (-3, 7) to the line
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