We sketch the curve first to see what is going on.
This is the curve `y=sin(x)`:
The shaded region represents the integral we need to find.
We need to split the integration into 2 portions because one part of the curve is above the `x`-axis (the part from `0` to `pi`), and the rest of it is below the `x`-axis (the part from `pi` to `(3pi)/2`, and we'll need to take the absolute value).
`"Area" =int_0^pi sin x\ dx+|int_pi^(3pi//2)sin x\ dx|`
`=[-cos x]_0^pi+` `|-cos x|_pi^(3pi//2)`
`=[-cos pi-(-cos 0)]+` `|-cos (3pi)/2-(-cos pi)|`