IntMath forum | Complex Numbers
Index problem [Solved!]
Rapelang 10 Dec 2015, 03:27
My question
What is the difference between (-1)^2/2 and ((-1)^2)^1/2?
Relevant page
2. Basic Operations in Complex Numbers
What I've done so far
I tried expanding each out using complex number laws, but I'm not sure what I'm doing.
X
What is the difference between (-1)^2/2 and ((-1)^2)^1/2?
Relevant page
<a href="/complex-numbers/2-basic-operations.php">2. Basic Operations in Complex Numbers</a>
What I've done so far
I tried expanding each out using complex number laws, but I'm not sure what I'm doing.
Re: Index problem
Newton 11 Dec 2015, 02:36
I'm not very clear what (-1)^2/2 means. (Please use the math input system - it makes it much easier for use to read your math.)
If we take the final 2 to mean "half of", then it probably means `((-1)^2)/2 = 1/2`
The second expression, `((-1)^2)^1/2` if written `((-1)^2)^(1/2)` means "the square root of `(-1)` squared".
In this case, `(-1)^2 = 1` and the square root of `1` is `1`.
Hope that helps.
X
I'm not very clear what (-1)^2/2 means. (Please use the math input system - it makes it much easier for use to read your math.)
If we take the final 2 to mean "half of", then it probably means `((-1)^2)/2 = 1/2`
The second expression, `((-1)^2)^1/2` if written `((-1)^2)^(1/2)` means "the square root of `(-1)` squared".
In this case, `(-1)^2 = 1` and the square root of `1` is `1`.
Hope that helps.
Re: Index problem
Rapelang 12 Dec 2015, 05:28
I found your solution very helpful,well part of it.
Actually what i meant was,is {(-1)^(1/2)}^2 a real number?
X
I found your solution very helpful,well part of it.
Actually what i meant was,is {(-1)^(1/2)}^2 a real number?Re: Index problem
Newton 12 Dec 2015, 20:14
Hi again
Yes, it is a real number.
You have the equivalent of the square of the imaginary number, `j`. The answer is real, and it is `-`1.
See half-way down this page:
1. Basic Definitions of Complex Numbers
X
Hi again
Yes, it is a real number.
You have the equivalent of the square of the imaginary number, `j`. The answer is real, and it is `-`1.
See half-way down this page:
<a href="/complex-numbers/1-basic-definitions.php">1. Basic Definitions of Complex Numbers</a>
Re: Index problem
Rapelang 13 Dec 2015, 10:07
Hi,it's me again.
What I think is that `{(-1)^(1/2)}^2=sqrt(-1)^2`,which is `j^2=-1`.
So I want to ask this,does it mean complex numbers are also REAL?
X
Hi,it's me again.
What I think is that `{(-1)^(1/2)}^2=sqrt(-1)^2`,which is `j^2=-1`.
So I want to ask this,does it mean complex numbers are also REAL?Re: Index problem
Newton 13 Dec 2015, 22:19
Hi again
Complex numbers consist of a real part and an imaginary part.
You can have the following and call them all complex.
`3 + 5j`
`3 + 0j`
`0 + 5j`
But really, the first is complex, the second is real, the 3rd is imaginary.
Good luck with it.
X
Hi again
Complex numbers consist of a real part and an imaginary part.
You can have the following and call them all complex.
`3 + 5j`
`3 + 0j`
`0 + 5j`
But really, the first is complex, the second is real, the 3rd is imaginary.
Good luck with it.
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