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IntMath forum | Complex Numbers

Complex conjugates [Solved!]

My question

In section 2 the part on dividing complex numbers, it is written that the numerator and denominator are multiplied by the conjugate so that
"we would be left with no radical (square root) in the denominator. Dividing with complex numbers is similar."

Does that mean that we divide by the conjugate so that no complex number will be left in the denominator?

Thank you.

Relevant page

2. Basic Operations in Complex Numbers

What I've done so far

X

In section 2 the part on dividing complex numbers, it is written that the numerator and denominator are multiplied by the conjugate so that 
"we would be left with no radical (square root) in the denominator. Dividing with complex numbers is similar."

Does that mean that we divide by the conjugate so that no complex number will be left in the denominator?

Thank you.
Relevant page

<a href="/complex-numbers/2-basic-operations.php">2. Basic Operations in Complex Numbers</a>

What I've done so far

Re: Complex conjugates

Hello Phinah. Not exactly (but I can understand why you took that meaning from it).

I revised that part just now on that page. I hope it makes more sense now.

X

Hello Phinah. Not exactly (but I can understand why you took that meaning from it).

I revised that part just now on that page. I hope it makes more sense now.

Re: Complex conjugates

Okay. I read it. Thank you.

X

Okay.  I read it.  Thank you.

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