# Complex conjugates [Solved!]

**phinah** 03 Aug 2017, 19:33

### My question

In section 2 the part on dividing complex numbers, it is written that the numerator and denominator are multiplied by the conjugate so that

"we would be left with no radical (square root) in the denominator. Dividing with complex numbers is similar."

Does that mean that we divide by the conjugate so that no complex number will be left in the denominator?

Thank you.

### Relevant page

2. Basic Operations in Complex Numbers

### What I've done so far

X

In section 2 the part on dividing complex numbers, it is written that the numerator and denominator are multiplied by the conjugate so that
"we would be left with no radical (square root) in the denominator. Dividing with complex numbers is similar."
Does that mean that we divide by the conjugate so that no complex number will be left in the denominator?
Thank you.

Relevant page
<a href="/complex-numbers/2-basic-operations.php">2. Basic Operations in Complex Numbers</a>
What I've done so far

## Re: Complex conjugates

**Murray** 06 Aug 2017, 05:08

Hello Phinah. Not exactly (but I can understand why you took that meaning from it).

I revised that part just now on that page. I hope it makes more sense now.

X

Hello Phinah. Not exactly (but I can understand why you took that meaning from it).
I revised that part just now on that page. I hope it makes more sense now.

## Re: Complex conjugates

**phinah** 18 Aug 2017, 15:21

Okay. I read it. Thank you.

X

Okay. I read it. Thank you.

## Re: Complex conjugates

**jyudeas** 30 Nov 2022, 02:59

Re: cookie clicker

I just now updated the section on that page. Now, perhaps, it all makes sense.

X

Re: <a href="https://cookieclickercity.com">cookie clicker</a>
I just now updated the section on that page. Now, perhaps, it all makes sense.

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