# 10. Reactance and Angular Velocity - Alternating Currents

by M. Bourne

## Alternating Currents

An alternating current is created by rotating a coil of wire through a magnetic field. If the angular velocity of the wire is ω, the

capacitive reactanceis given by:`X_C=1/(omegaC)`

inductive reactanceis given by:

X_{L}= ωL

## Example

If `R = 10\ Ω`, `L = 0.6\ "H"`, `C = 200\ mu "F"` and ` ω = 50\ "rad/s"`, find the magnitude of the impedance and the phase difference between the current and the voltage.

Answer

Recall: `μ` (micro) means `10^-6`.

Capacitive Reactance:

`X_C=1/(omegaC)`

`=1/((50)(200xx10^-6))`

`=100\ Omega`

Inductive Reactance `X_L= ωL = 50 × 0.6 = 30\ Ω`

`X_L − X_C= 30 - 100 = -70\ Ω`

`Z = 10 - 70j\ Ω` in rectangular form.

Using calculator, `|Z| = 70.71\ Ω` and ` θ = -81.87^@`.

So `Z = 70.71\ ∠\ -81.87^@\ Ω`

So the **magnitude of the impedance** is `70.71\ Ω` and the
voltage **lags** the current by `81.87^@` (this is the
**phase difference**).

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## Angular Velocity and Frequency

In this section, recall that angular velocity and frequency are related by the expression:

ω= 2πf

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