In this case, `X_L= 3\ Ω` and `X_C= 0` so `X_L- X_C= 3\ Ω`.
So in rectangular form, the impedance is written:
`Z = 5 + 3j\ Ω`
Using calculator, the magnitude of Z is given by: `5.83`, and the angle `θ` (the phase difference) is given by: `30.96^@`.
So the voltage leads the current by `30.96^@`, as shown in the diagram.
Presenting Z as a complex number (in polar form), we have:
`Z = 5.83 ∠ 30.96^@\ Ω`.