Using the Table of Laplace Transforms, we have:

MATH

For

MATH

we think of it as

MATH

and use rule (4) from above:

$\tciLaplace ^{-1}$ $\{$ $e^{-as}$ $G(s)\}$ $=$ $u(t-a)\cdot g(t-a)$

Now, MATH

so MATH MATH

Similarly, MATH MATH

So


MATH

= 2u(t − 2) + (t − 2) • u(t − 2) − 3u(t − 3) − (t − 3) • u(t − 3)

= 2u(t − 2) + tu(t − 2) − 2 • u(t − 2) − 3 • u(t − 3) − t u(t − 3) + 3 • u(t − 3)

= t • [u(t − 2) − u(t − 3)]

So

g(t) = t • (u(t − 2) − u(t − 3))
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