8. Using Inverse Laplace Transforms to Solve Differential Equations
Laplace Transform of Derivatives
We use the following notation:
(a) If we have the function g(t), then G(s) = G =
{g(t)}.
(b) g(0) is the value of the function g(t) at t = 0.
(c) g'(0), g''(0),... are the values of the derivatives of the function at t = 0.
If g(t) is continuous and g'(0), g''(0),... are finite, then
(1)
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(2)
{g''(t)} = s2G − s g(0) − g'(0)
We saw many of these expressions in the Table of Laplace Transforms.
NOTE: If instead of g(t) we have a function y of x, then Equation (2) would simply become:
{y''(x)} = s2Y − s y (0) − y'(0)
Likewise, if we have an expression for current i and it is a function of t, then the equation would become:
{i''(t)} = s2I − s i(0) − i'(0)
(3) For the n-th derivative,

NOTE: If we have y and it is a function of t, then the notation would become:

Subsidiary Equation
The subsidiary equation is the equation in terms of s, G and the coefficients g'(0), g''(0),... etc ,obtained by taking the transforms of all the terms in a linear differential equation.
The subsidiary equation is expressed in the form G = G(s).
EXAMPLES
Write down the subsidiary equations for the following differential equations and hence solve them.
(a)
, given that y = 0 when t = 0.
Scientific Notebook solution:
This is the way we could go about this problem using Scientific Notebook. You don't need any special software to see it (it is in HTML form.)
(b) Solve
, given that
y = 1,
, when t = 0.
Scientific Notebook solution:
(c)
, given that
y = -2,
, when t = 0.
Scientific Notebook solution:
APPLICATION
The current i(t) in an electrical circuit is given by the DE

and i(0) = 0, i'(0) = 0.
Determine the current as a function of t.
Scientific Notebook solution:
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