We need to find

`y=int sqrt(e^(x+3))dx,`

and subsitute our given conditions to find the equation of the curve.

Put `u = x + 3` then `du = dx`. Perform the integral.

`y=intsqrt(e^(x+3)) dx`

`=intsqrt(e^u) du`

`=inte^(u//2) du`



Now, the curve passes through `(1, 0)`.

This means when `x = 1`, `y = 0`.

So `0=2e^2+K`, giving `K = -2e^2`.

So the required equation of the curve is:



Please support IntMath!