Differentiating tanh [Solved!]
Haida 26 Nov 2015, 08:13
My question
what the answer if we differentiate `y = tanh (x-9)`?
Relevant page
Differentiation of Transcendental Functions
What I've done so far
I tried to find this on IntMath, but couldn't.
Haida 26 Nov 2015, 08:13
what the answer if we differentiate `y = tanh (x-9)`?
Differentiation of Transcendental Functions
I tried to find this on IntMath, but couldn't.
X
what the answer if we differentiate `y = tanh (x-9)`?
Relevant page <a href="/differentiation-transcendental/differentiate-transcendental-intro.php">Differentiation of Transcendental Functions</a> What I've done so far I tried to find this on IntMath, but couldn't.
Murray 26 Nov 2015, 16:36
Hello Haida
This is not "`tan`", but `"tanh`".
IntMath doesn't include the hyperbolic functions (yet), but you can see the formula for differentiating `tanh x` at:
Your situation is a function of function situation. Do you think you can do it now?
Good luck with it.
Regards
M Bourne
X
Hello Haida This is not "`tan`", but `"tanh`". IntMath doesn't include the hyperbolic functions (yet), but you can see the formula for differentiating `tanh x` at: <a href="/differentiation-transcendental/table-derivatives.php">Table of Derivatives</a> Your situation is a function of function situation. Do you think you can do it now? Good luck with it. Regards M Bourne
Haida 27 Nov 2015, 13:38
I think it's
Put `u=x-9` so `y= tanh u`.
Then `dy/dx = dy/(du) (du)/dx`
` = (1-tanh^2 u)(du)/dx = 1 - tanh^2(x-9)`.
Is it OK?
X
I think it's Put `u=x-9` so `y= tanh u`. Then `dy/dx = dy/(du) (du)/dx` ` = (1-tanh^2 u)(du)/dx = 1 - tanh^2(x-9)`. Is it OK?
X
Yes, you've nailed it. Well done.
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