# ODE seperable method [Pending...]

**Ahmed** 13 Oct 2016, 22:18

### My question

(y/x)*(dy/dx)=sqrt(1+x^2+y^2+x^2*y^2)

### Relevant page

Differential Equations - Separable Equations

### What I've done so far

replaced 1+x^2+y^2+x^2*y^2 with t

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**Ahmed** 13 Oct 2016, 22:18

(y/x)*(dy/dx)=sqrt(1+x^2+y^2+x^2*y^2)

Differential Equations - Separable Equations

replaced 1+x^2+y^2+x^2*y^2 with t

X

(y/x)*(dy/dx)=sqrt(1+x^2+y^2+x^2*y^2)

Relevant page <a href="http://tutorial.math.lamar.edu/Classes/DE/Separable.aspx">Differential Equations - Separable Equations</a> What I've done so far replaced 1+x^2+y^2+x^2*y^2 with t

**Murray** 14 Oct 2016, 20:33

Hello Ahmed

You are encouraged to use the Math Input system so your math is easier to read.

Then your question looks like this:

`(y/x)(dy/dx)=sqrt(1+x^2+y^2+x^2*y^2)`

The first hint is to factor the expression under the square root. Do that first, then we'll go from there.

X

Hello Ahmed You are encouraged to use the <a href="/forum/entering-math-graphs-images-41/how-to-enter-math:91">Math Input system</a> so your math is easier to read. Then your question looks like this: `(y/x)(dy/dx)=sqrt(1+x^2+y^2+x^2*y^2)` The first hint is to factor the expression under the square root. Do that first, then we'll go from there.

**Ahmed** 14 Oct 2016, 22:19

Ok I've factorised it now it looks like

(y/x)*(dy/dx)=sqrt((x^2+1)(y^2+1))

now what.

X

Ok I've factorised it now it looks like (y/x)*(dy/dx)=sqrt((x^2+1)(y^2+1)) now what.

**Murray** 16 Oct 2016, 20:10

Putting back ticks around your (correct) answer makes it appear as:

`(y/x)*(dy/dx)=sqrt((x^2+1)(y^2+1))`

OK, now you need to separate the variables. That is, put all the `y` and `dy` parts together on the left, and the `x` and `dx` parts together on the right.

X

Putting back ticks around your (correct) answer makes it appear as: `(y/x)*(dy/dx)=sqrt((x^2+1)(y^2+1))` OK, now you need to separate the variables. That is, put all the `y` and `dy` parts together on the left, and the `x` and `dx` parts together on the right.

**Murray** 26 Oct 2016, 23:38

It seems Ahmed has disappeared. Anyone else like to have a go at finishing it?

X

It seems Ahmed has disappeared. Anyone else like to have a go at finishing it?

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