We use the substitutions u = 2x2 + 6x and v = 2x3 + 5x2.

We can then use the PRODUCT RULE:

`(d(uv))/(dx)=u(dv)/(dx)+v(du)/(dx`

We first find: `(dv)/(dx)=6x^2+10x` and `(du)/(dx)=4x+6`

Then we can write:

`(d(uv))/(dx)=u(dv)/(dx)+v(du)/(dx)`

`=(2x^2+6x)(6x^2+10x)+(2x^3+5x^2)(4x+6)`

`=20x^4+88x^3+90x^2`

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