First we must separate the variables:
This gives us: `(2\ dy)/y=(1+1/x)dx`
We now integrate:
`2 ln y=x+ln x+K`
Go back to Integration: Basic Logarithm Form if you are rusty on this integration.
We could continue with our solution and express `y` as an explicit function of `x`, as follows:
`ln y=(x+ln x+K)/2`
Taking a typical constant value `K=1`, we have this solution graph:
Typical solution graph `y=e^((x+ln x+1)//2)`.
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