Let E1 = first die is `6`;

Let E2 = total of two dice is ` > 8`

Then "E1 and E2" will be given by `(6, 3),\ (6, 4),\ (6, 5),\ (6, 6)`.

There are `36` possible outcomes when we throw 2 dice.

So

`P(E_2\ "and"\ E_1)=4/36=1/9`

Therefore

`P(E_2|E_1)` `= frac{P(E_2\ "and"\ E_1)}{P(E_1)}` `=frac{1/9}{1/6}=6/9` `=2/3`

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