We have `r = 5` from the question.

We must express ` θ = 135^@` in radians.

Recall:

`1^text(o)=pi/180`

So

`135^text(o)=(135pi)/180`

`=(3pi)/4`

`~~2.36` radians

So we can write

`5(cos\ 135^text(o)+j\ sin135^text(o))`

`=5e^((3pij)/4)`

` ~~ 5e^(2.36j)`

Get the Daily Math Tweet!
IntMath on Twitter