# 6. Algebraic Solution of Systems of Equations

## Solution by Substitution

Similar to the linear case in the previous section, we can solve a system of equations by substitutiong one of the expressions given into the other expression. Our solution will be a set of x-y coordinates.

### Example 1

Solve the system of equations algebraically:

y = x + 1

x2 + y2 = 25

## Solution by Addition or Subtraction

This method works by eliminating one of the variables from the equations. We then find the value(s) of the remaining variable.

### Example 2

Solve the system of equations by adding or subtracting

x2 + y = 5

x2 + y2 = 25

### Exercises

1. Solve algebraically:

6y x = 6

x2 + 3y2 = 36

2. Solve algebraically:

3x2y2 = 4

x2 + 4y2 = 10

3. An alternating current has impedance given by Z = 2.00 Ω. If the resistance R in the circuit is numerically equal to the square of the reactance X, find R and X.

4. Find the intersection points for the circles

(x + 2)2 + (y − 3)2 = 25

and

(x − 1)2 + (y + 4)2 = 16

top

### Online Algebra Solver

This algebra solver can solve a wide range of math problems.

### Algebra Lessons on DVD

Easy to understand algebra lessons on DVD. See samples before you commit.

More info: Algebra videos

### The IntMath Newsletter

Sign up for the free IntMath Newsletter. Get math study tips, information, news and updates each fortnight. Join thousands of satisfied students, teachers and parents!

Given name: * required

Family name:

email: * required

See the Interactive Mathematics spam guarantee.