IntMath Home » Forum home » Analytic Trigonometry » Hyperbolic functions

IntMath forum | Analytic Trigonometry

Hyperbolic functions [Solved!]

My question

Hi,

I have this problem to solve:

1 + (e2A-e-2A/2) + (e2A+e-2A/2)
----------------------------------
1 - (e2A-e-2A/2) - (e2A+e-2A/2)

The (2A) is are the the power of (e)

Can you help me simplify this please?

Thanks
Matt

Relevant page

Analytic Trigonometry

What I've done so far

Expanded it out and tried to simplfy, but couldnt do it

X

Hi,

I have this problem to solve:

1 + (e2A-e-2A/2) + (e2A+e-2A/2)
----------------------------------
1 - (e2A-e-2A/2) - (e2A+e-2A/2)

The (2A) is are the the power of (e)

Can you help me simplify this please?

Thanks
Matt
Relevant page

<a href="/analytic-trigonometry/analytic-trigo-intro.php">Analytic Trigonometry</a>

What I've done so far

Expanded it out and tried to simplfy, but couldnt do it

Re: Hyperbolic functions

Hello Matt

I suspect your brackets are in the wrong place. (The "/2" should be outside the bracket, yes?)

I don't have hyperbolic functions on IntMath (yet). You can go to this page for more information:

Hyperbolic function

I suggest that you write out carefully the top and bottom of your fraction and you will see some things disappear. Then try to recognise what you have got in the "Standard Algebraic Expressions" on that Wikipedia site. It's one of the expressions listed there.

I also suggest you use the math entry system so it's easier for you - and us - to read your math.

I hope that helps. There is not much to do in this problem - just simplify and then recognise.

Regards

X

Hello Matt

I suspect your brackets are in the wrong place. (The "/2" should be outside the bracket, yes?)

I don't have hyperbolic functions on IntMath (yet). You can go to this page for more information:

<a href="https://en.wikipedia.org/wiki/Hyperbolic_trigonometric_function">Hyperbolic function</a>

I suggest that you write out carefully the top and bottom of your fraction and you will see some things disappear. Then try to recognise what you have got in the "Standard Algebraic Expressions" on that Wikipedia site. It's one of the expressions listed there.

I also suggest you use the math entry system so it's easier for you - and us - to read your math.

I hope that helps. There is not much to do in this problem - just simplify and then recognise.

Regards

Re: Hyperbolic functions

Yah, it's better using the math writing system.

This was the question (you're right, I was missing some brackets):

`(1 + (e^(2A)-e^(-2A)/2) + (e^(2A)+e^(-2A)/2)) / (1 - (e^(2A)-e^(-2A)/2) - (e^(2A)+e^(-2A)/2))`

I still don't know what to do next.

X

Yah, it's better using the math writing system.

This was the question (you're right, I was missing some brackets):

`(1 + (e^(2A)-e^(-2A)/2) + (e^(2A)+e^(-2A)/2)) / (1 - (e^(2A)-e^(-2A)/2) - (e^(2A)+e^(-2A)/2))`

I still don't know what to do next.

Re: Hyperbolic functions

Are you sure you've got the right expression?

I suspect you are still missing some brackets there!

X

Are you sure you've got the right expression?

I suspect you are still missing some brackets there!

Re: Hyperbolic functions

`(1 + (e^(2A)-e^(-2A))/2 + (e^(2A)+e^(-2A))/2) / (1 - (e^(2A)-e^(-2A))/2 - (e^(2A)+e^(-2A))/2)`

That looks better! What do I do now?

X

`(1 + (e^(2A)-e^(-2A))/2 + (e^(2A)+e^(-2A))/2) / (1 - (e^(2A)-e^(-2A))/2 - (e^(2A)+e^(-2A))/2)`

That looks better! What do I do now?

Re: Hyperbolic functions

Now that I've seen your actual question, it rings a bell. It's the same as this forum question:

Trigonometry equation

Hope it helps.

X

Now that I've seen your actual question, it rings a bell. It's the same as this forum question:

<a href="http://www.intmath.com/forum/analytic-trigonometry-25/trigonometry-equation:16">Trigonometry equation</a>

Hope it helps.

Re: Hyperbolic functions

It did. I appreciate your help.

X

It did. I appreciate your help.

Reply

You need to be logged in to reply.

Search IntMath, blog and Forum