Chapter Contents

• Analytic Trigonometry
• 1. Trigonometric Identities
• 2. Sin, cos tan of Sum of Two Angles
• 3. Double Angle Formulas
• 4. Half Angle Formulas
• 5. Trigonometric Equations
• 6. Express in the form R sin (θ + α)
• 7. Inverse Trigonometric Functions
• Analytic Trigonometry Problem Solver

• Comments, Questions?

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3. Double-Angle Formulas

by M. Bourne

The double-angle formulas can be quite useful when we need to simplify complicated trigonometric expressions later.

With these formulas, it is better to remember where they come from, rather than trying to remember the actual formulas. In this way, you will understand it better and have less to clutter your memory with.

Sine of a Double Angle

Recall from the last section, the sine of the sum of two angles:

sin(α + β) = sin α cos β + cos α sin β

We will use this to obtain the sine of a double angle.

If we take the left hand side:

sin(α + β)

and replace β with α, we get:

sin(α + β) = sin(α + α) = sin 2α

Consider the RHS:

sin α cos β + cos α sin β

If we replace β with α, we obtain:

sin α cos α + cos α sin α = 2 sin α cos α

Putting our results for the LHS and RHS together, we obtain the important result:

sin 2α = 2 sin α cos α

This result is called the sine of a double angle. It is useful for simplifying expressions later.

Cosine of a Double Angle

Using a similar process, we can start with the cosine of the sum of two angles

cos(α + β) = cos α cos β − sin α sin β,

and obtain the cosine of a double angle formula:

cos 2α = cos2 α − sin2 α

By using the result sin² α + cos² α = 1, (which we found in Trigonometric Identities) we can write the RHS of the above formula as:

cos² α − sin² α

= (1− sin² α) − sin² α

= 1− 2sin² α

Likewise, we can substitute (1 − cos ² α) for sin² α into our RHS and obtain:

cos² α − sin² α

= cos² α − (1 − cos² α)

= 2cos² α − 1

Summary - Cosine of a Double Angle

The following have equivalent value, and we can use whichever one we like, depending on the situation:

cos 2α = cos2 α − sin2 α

cos 2α = 1− 2sin2 α

cos 2α = 2cos2 α − 1

Example 1

Find cos 60° by using the functions of 30°.

Answer

Example 2

Find `cos\ 2x` if `sin\ x= -12/13` (in Quadrant III).

Answer

Exercises

1. Without finding `x`, find `sin\ 2x` if `cos\ x= 4/5` (in Quadrant I).

Answer

2. Prove that

`(1-tan^2x)/(sec^2x)=cos2x`

Answer

3. Prove that

`2\ csc\ 2x\ tan\ x = sec^2x`

Answer