2. Derivatives of Csc, Sec and Cot Functions

by M. Bourne

By using the quotient rule and trigonometric identities, we can obtain the following derivatives:

math expression

In words, we would say:

The derivative of csc x is -csc x cot x,
The derivative of sec x is sec x tan x and
The derivative of cot x is -csc2x.

If u = f(x) is a function of x, then by using the chain rule, we have:

math expression

Example 1:

Find the derivative of s = sec(3t + 2).

Example 2:

Find the derivative of x = θ3 csc 2θ.

Example 3:

Find the derivative of y = sec43x.

Exercises

1. Find the derivative of y = csc2(2x2).

2. Find the derivative of y = sec2 2x.

3. Find the derivative of 3 cot(x + y) = cos y2.

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