4. The Graph of the Quadratic Function
In general, the graph of a quadratic equation
y = ax2 + bx + c
is a parabola.
[You can also see a more detailed description of parabolas in the Plane Analytic Geometry section.]
If a > 0, then the parabola has a minimum point and it opens upwards (U-shaped) eg.
y = x2 + 2x − 3

If a < 0, then the parabola has a maximum point and it opens downwards (n-shaped) eg.
y = -2x2 + 5x + 3

Sketching Parabolas
In order to sketch the graph of the quadratic equation, we follow these steps :
(a) Check if a > 0 or a < 0 to decide if it is U-shaped or n-shaped.
(b) The Vertex: The x-coordinate of the minimum point (or maximum point) is given by
(which can be shown using completing the square method, which we met earlier).
We substitute this x-value into our quadratic function (the y expression). Then we will have the (x, y) coordinates of the minimum (or maximum) point. This is called the vertex of the parabola.
(c) The coordinates of the y-intercept (substitute x = 0). This is always easy to find!
(d) The coordinates of the x-intercepts (substitute y = 0 and solve the quadratic equation), as long as they are easy to find.
Example 1
Sketch the graph of the function y = 2x2 − 8x + 6
Let's see the graph of this quadratic function using LiveMath. Play and enjoy!
Normal answer
We first identify that a = 2, b = -8 and c = 6.
Step (a) Since a = 2, a > 0 hence the function is a parabola with a minimum point and it opens upwards (U-shaped)
Step (b) The x co-ordinate of the minimum point is:
The y value of the minimum point is
y = 2(2)2 - 8(2) + 6 = -2
So the minimum point is (2, -2)
Step (c) The y-intercept is found by substituting x = 0 into the y expression.
y = 2(0)2 - 8(0) + 6 = 6
So (0, 6) is the y-intercept.
Step (d) The x-intercepts are found by setting y = 0 and solving:
2x2 - 8x + 6 = 0
2(x2 - 4x + 3) = 0
2(x - 1)(x - 3) = 0
So x = 1, or x = 3.
Using the above information, the sketch of the curve will be :
Investigate Solutions of Quadratic Equations Using LiveMath
Now see if you really know what's going on. Try this LiveMath challenge.
Example 2
Sketch the graph of the function y = -x2 + x + 6
Exercise
Sketch the graph y = -x2 − 4x − 3
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