2. Derivatives of Csc, Sec and Cot Functions

by M. Bourne

By using the quotient rule and trigonometric identities, we can obtain the following derivatives:

math expression

In words, we would say:

The derivative of csc x is -csc x cot x,
The derivative of sec x is sec x tan x and
The derivative of cot x is -csc2x.

If u = f(x) is a function of x, then by using the chain rule, we have:

math expression

 

Example 1:

Find the derivative of s = sec(3t + 2).


Answer

You can change the function in this LiveMath document.

LIVEMath

 

Example 2:

Find the derivative of x = θ3 csc 2θ.

Answer

 

Example 3:

Find the derivative of y = sec43x.

Answer


Exercises

1. Find the derivative of y = csc2(2x2).

 

Answer


2. Find the derivative of y = sec2 2x.

Answer


3. Find the derivative of 3 cot(x + y) = cos y2.

Answer




Didn't find what you are looking for on this page? Try search:

Calculus Lessons on DVD

get MathTutorDVDs

Easy to understand calculus lessons on DVD. See samples before you commit.

More info: Calculus videos

 

Bookmark this page

Add this page to diigo, Redditt, etc.

 

Like Us on Facebook!

The IntMath Newsletter

Sign up for the free IntMath Newsletter. Get math study tips, information, news and updates each fortnight. Join thousands of satisfied students, teachers and parents!

Given name: * required

Family name:

email: * required

See the Interactive Mathematics spam guarantee.

 

Need a break? Play a math game. Well, they all involve math... No, really!

dumbolf memoTST bola shadow factory mindfields trick-hoops-challenge crystal clear