IntMath forum | Matrices and Determinants
linear transformation [Solved!]
Hans4386 26 Oct 2016, 10:14
My question
T:M22->M22 be defined by T([matrix row 1: a b, row 2: c d])= [matrix row 1: 2c a+c, row 2: b-2c d].
To find the eigenvalues of T
(This question is quoted from exercise of section 8.5 of book "Elementary Linear Algebra Application Version" by Howard Anton and Chris Rorres)
Relevant page
4. Multiplication of Matrices
What I've done so far
I tried to find the [T][row 1: a b, row 2: c d]=[row 1: 2c a+c, row 2: b-2c d] but can't find a 2*2 matrix fits [T];
I also tried to separate [row 1: 2c a+c, row 2: b-2c d] into [row 1: c a, row 2:b d] + c[row 1: 1 1, row 2: -2 0] and then ??
X
T:M22->M22 be defined by T([matrix row 1: a b, row 2: c d])= [matrix row 1: 2c a+c, row 2: b-2c d].
To find the eigenvalues of T
(This question is quoted from exercise of section 8.5 of book "Elementary Linear Algebra Application Version" by Howard Anton and Chris Rorres)
Relevant page
<a href="/matrices-determinants/4-multiplying-matrices.php">4. Multiplication of Matrices</a>
What I've done so far
I tried to find the [T][row 1: a b, row 2: c d]=[row 1: 2c a+c, row 2: b-2c d] but can't find a 2*2 matrix fits [T];
I also tried to separate [row 1: 2c a+c, row 2: b-2c d] into [row 1: c a, row 2:b d] + c[row 1: 1 1, row 2: -2 0] and then ??
Re: linear transformation
Murray 26 Oct 2016, 23:36
Hi Hans
You are encouraged to use the math entry system in this forum to make your math easier to read.
Your question becomes:
`T:M{2,2}->M{2,2}` be defined by `T[(a,b), (c, d)] = [(2c, a+c), (b-2c, d)].`
Your attempts will appear as:
I tried to find the `[T][(a,b), (c, d)] = [(2c, a+c), (b-2c, d)]` but can't find a 2*2 matrix fits [T];
I also tried to separate `[(2c, a+c), (b-2c, d)]` into `[(c, a), (b, d)] + c[(1, 1), (-2, 0)]` and then ??
(You can click on the "Show code" button to see how I created those matrices.)
Let's put `A = [(a,b), (c, d)]` and `B = [(2c, a+c), (b-2c, d)]`.
We are trying to find a `2xx2` matrix `T` such that `TA = B`, right?
My hint: What happens if you multiply both sides on the right by `A^-1`?
X
Hi Hans
You are encouraged to use the math entry system in this forum to make your math easier to read.
Your question becomes:
<blockquote>
`T:M{2,2}->M{2,2}` be defined by `T[(a,b), (c, d)] = [(2c, a+c), (b-2c, d)].`
</blockquote>
Your attempts will appear as:
<blockquote>
I tried to find the `[T][(a,b), (c, d)] = [(2c, a+c), (b-2c, d)]` but can't find a 2*2 matrix fits [T];
I also tried to separate `[(2c, a+c), (b-2c, d)]` into `[(c, a), (b, d)] + c[(1, 1), (-2, 0)]` and then ??
</blockquote>
(You can click on the "Show code" button to see how I created those matrices.)
Let's put `A = [(a,b), (c, d)]` and `B = [(2c, a+c), (b-2c, d)]`.
We are trying to find a `2xx2` matrix `T` such that `TA = B`, right?
<b>My hint:</b> What happens if you multiply both sides on the right by `A^-1`?Re: linear transformation
Hans4386 28 Oct 2016, 01:20
Dear Murray,
Much thank for your hints, I worked out the matrix [T] as
`1/(ad-bc)[(2cd-ac-c^2, ac-2bc+a^2),(bd-3cd,2bc+ad-b^2)]`
however I can't make the answer match with the textbook in which the answer of the eigenvalues are 1, -2, -1. Also I tried to work out the eigenvalue from `lambda*I-T`, the roots of the characteristic equation are very complicated that I think I am going in the wrong way, also I wonder how comes to have 3 eigenvalues from 2nd order characteristic equation?
X
Dear Murray,
Much thank for your hints, I worked out the matrix [T] as
`1/(ad-bc)[(2cd-ac-c^2, ac-2bc+a^2),(bd-3cd,2bc+ad-b^2)]`
however I can't make the answer match with the textbook in which the answer of the eigenvalues are 1, -2, -1. Also I tried to work out the eigenvalue from `lambda*I-T`, the roots of the characteristic equation are very complicated that I think I am going in the wrong way, also I wonder how comes to have 3 eigenvalues from 2nd order characteristic equation?
Re: linear transformation
Murray 29 Oct 2016, 07:09
Hi Hans
Your answer for T is correct, assuming it's matrix multiplication that the question was aiming for. I agree with you that solving the characteristic equation would be horrible, and there shouldn't be 3 eigenvalues! Is there something wrong with the question, or some context that we are both missing?
X
Hi Hans
Your answer for T is correct, assuming it's matrix multiplication that the question was aiming for. I agree with you that solving the characteristic equation would be horrible, and there shouldn't be 3 eigenvalues! Is there something wrong with the question, or some context that we are both missing?
Re: linear transformation
Murray 29 Dec 2016, 14:23
It seems Hans has disappeared. I'll close this topic in the absence of any further information.
X
It seems Hans has disappeared. I'll close this topic in the absence of any further information.
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