# Equivalent Fractions [Solved!]

### My question

HELP 6x^2+13x-5/6x^3-2x^2
divide (3x-1) to denominator and numerator
please show me how to solve this

### Relevant page

5. Equivalent Fractions

### What I've done so far

Tried to do it sseveral ways but got stuck

X

HELP 6x^2+13x-5/6x^3-2x^2
divide (3x-1) to denominator and numerator
please show me how to solve this
Relevant page

<a href="/factoring-fractions/5-equivalent-fractions.php">5. Equivalent Fractions</a>

What I've done so far

Tried to do it sseveral ways but got stuck

## Re: Equivalent Fractions

You can factor both the top and the bottom of that fraction. (A big hint is that (3x-1) will go into both top and bottom.)

6. Multiplication and Division of Fractions

You factor everything first, then you can divide top and bottom.

Can you go from there?

BTW, if you use the math input system, you can make much more readable math, like this:

\frac{6x^2+13x-5}{6x^3-2x^2}

Regards

X

Hello Taradawn

You can factor both the top and the bottom of that fraction. (A big hint is that (3x-1) will go into both top and bottom.)

<a href="/factoring-fractions/6-multiplication-division-fractions.php">6. Multiplication and Division of Fractions</a>

You factor everything first, then you can divide top and bottom.

Can you go from there?

BTW, if you use the math input system, you can make much more readable math, like this:

\frac{6x^2+13x-5}{6x^3-2x^2}

Regards

## Re: Equivalent Fractions

i try

6x^2+13x-5/6x^3-2x^2  = (3x - 1)(2x + 5)/2x^2(3x-1)

But when I do "Preview", the math looks bad. Why?

X

i try

6x^2+13x-5/6x^3-2x^2  = (3x - 1)(2x + 5)/2x^2(3x-1)

But when I do "Preview", the math looks bad. Why?

## Re: Equivalent Fractions

Your answer so far is good, but you need to remember to use brackets so the fractions work properly.

6x^2+13x-5/6x^3-2x^2 = (3x - 1)(2x + 5)/2x^2(3x-1)

it should be

(6x^2+13x-5)/(6x^3-2x^2) = ((3x - 1)(2x + 5))/(2x^2(3x-1))

so it looks like

(6x^2+13x-5)/(6x^3-2x^2) = ((3x - 1)(2x + 5))/(2x^2(3x-1))

X

Your answer so far is good, but you need to remember to use brackets so the fractions work properly.

<code>6x^2+13x-5/6x^3-2x^2 = (3x - 1)(2x + 5)/2x^2(3x-1)</code>

it should be

<code>(6x^2+13x-5)/(6x^3-2x^2) = ((3x - 1)(2x + 5))/(2x^2(3x-1))</code>

so it looks like

(6x^2+13x-5)/(6x^3-2x^2) = ((3x - 1)(2x + 5))/(2x^2(3x-1))

## Re: Equivalent Fractions

OK, got it.

I've factored, so now I can cancel:

(6x^2+13x-5)/(6x^3-2x^2)  = ((3x - 1)(2x + 5) -: (3x-1))/(2x^2(3x-1) -: (3x-1))  = (2x+5)/(2x^2)

Am I right?

X

OK, got it.

I've factored, so now I can cancel:

(6x^2+13x-5)/(6x^3-2x^2)  = ((3x - 1)(2x + 5) -: (3x-1))/(2x^2(3x-1) -: (3x-1))   = (2x+5)/(2x^2)

Am I right?

## Re: Equivalent Fractions

Yes, well done!

X

Yes, well done!

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