The notation

`y = x(ln^3 x)`


`y = x(ln x)^3`

Note that we cannot use the log law

`log a^n= n log a`

Our expression is not

`y = x\ ln x^3`

The brackets make all the difference!

This is a product of x and `(ln x)^3`. So

`(dy)/(dx)=x(3(ln x)^2)/x+(ln x)^3(1)`

`=3(ln x)^2+(ln x)^3`

`=(ln x)^2(3+ln x)`

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