We
can think of `(6x^2+6+7x)/(2x+1)` as (6*x*^{2} + 7*x* + 6) ÷ (2*x* + 1)

Once again we are dividing a polynomial of degree 2 by a polynomial of lower degree (1). This is algebraic long division.

**Step 1:** 6*x*^{2} ÷ 2*x* = 3*x*

So we write the following, using (3*x*)(2*x* + 1) = 6*x*^{2} + 3*x* for the second row:

**Step 2: **We subtract 6*x*^{2} + 3*x* from the first row:

**Step 3:** Bring down the 6:

**Step 4: **Divide 4*x* by 2*x*. Our answer is 2 and we multiply 2(2*x* + 1) to get the 4th row.

**Step 5: ** Subtract, and we are left with 4.

So the answer is:

`(6x^2+6+7x)/(2x+1)=3x+2+4/(2x+1)`

**NOTE: **Some people prefer to write the problem with all the *x*^{2}'s, *x*'s and units in line, as follows:

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