Graph of `y=x^3`, showing the portion bounded by `x = 0` and `y=3`.
We will use:
and use horizontal elements. (In this example we could have added horizontally as well, but will do it vertically to illustrate the method.)
In this case, `c = 0` and `d = 3`.
We need to express `x` in terms of `y`:
`y = x^3` so `x = y^(1//3)`
`=int_0^3 (y^(1//3)) dy`
`=3.245\ text[sq units]`