The first equation is a hyperbola, while the second is an ellipse.
We multiply the first row by 4 so we can eliminate the `y^2` term:
Now adding the two rows, we obtain:
Substituting `+sqrt(2)` into the question's first equation gives us
Likewise, substituting `-sqrt(2)` into the first equation also gives us
This gives us the solutions
`(sqrt(2),sqrt(2)),` `(sqrt(2),-sqrt(2)),` `(-sqrt(2),sqrt(2)),` `(-sqrt(2),-sqrt(2)) `
≈ (±1.414, ±1.414), (±1.414, ∓1.414)
The graph shows the intersection of the ellipse and the hyperbola. We see 4 intersection points, with the same values that we found algebraically.
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