From line [1], we subtract *x* from both sides and get `y = −x + 3`.

We substitute this in the place of *y* in line [2]:

3

x− 2(−x+ 3) = 14

This gives us: `3x + 2x − 6 = 14`

Therefore `x = 4`.

Now, using line [1] we get ` y = −1`.

If we have the right numbers, they should also work in the other equation.

Checking in line [2]:

`3(4) − 2(−1) = 14`

[OK]

So our solution `(4, −1)` is correct.

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