We need to find the intersection of the "true" values.

`x - 1 < 2x + 2` and `2x + 2 < 3x + 1`

`x < 2x + 3` and `2x < 3x - 1`

`x > -3` and `x > 1`

These 2 inequalities on the one axis appear as follows:

The intersection of these 2 regions is `x > 1`.

Always check your answers!

Here's the final solution graph: