Squaring both sides gives:

`3x+4 = x^2`

`x^2 - 3x - 4 = 0`

`(x-4)(x+1)=0`

So our solutions are `x = 4` and `-1`.

CHECK:

Substituting `x = 4` in our original equation gives:

`"LHS" = sqrt(3(4) + 4)=sqrt16 = 4`

`"RHS" = 4`

Checks OK

Substituting `x = -1` in our original equation gives:

`"LHS" = sqrt(3(-1) + 4)=sqrt1 = 1`

`"RHS" = -1`

DOES NOT check OK

So we conclude the only solution is `x = 4`.

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