Here, `b = 8`, so the period is `(2π)/8 = π/4.` To draw 2
cycles, we will need to graph from `0` to ` π/2` along the *x*-axis.

The graph of `y=3cos(8x)` for `0 ≤ x ≤ pi/2`

**Note** that we started the graph at `x = 0`, but we could have started anywhere. As long as we draw exactly 2 cycles, we are answering the question.

Now for interest, let's see what it looks like from `0` to
2*π*.

The graph of `y=3cos(8x)` for `0 ≤ x ≤ 2pi`

**Note** that there are **8** cycles between `0` and 2*π*.