In using the binomial formula, we let

`a = 2x,` `b = 3` and `n = 4.`

Substituting in the binomial formula, we get:

`(2x+3)^4`

`=(2x)^4+4(2x)^3(3)` `+(4(3))/(2!)(2x)^2(3)^2` `+(4(3)(2))/(3!)(2x)(3)^3+(3)^4`

`=16x^4+96x^3+216x^2+216x+81`

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