In using the binomial formula, we let

`a=x,` `b=2,` and `n=6`.

Substituting in the binomial formula, we get :

`(x+2)^6`

`=(x)^6 +6(x)^5(2)` `+(6(5))/(2!) (x)^4(2)^2` `+(6(5)(4))/(3!)(x)^3(2)^3` `+(6(5)(4)(3))/(4!) (x)^2(2)^4 ` `+(6(5)(4)(3)(2))/(5!) (x)(2)^5+(2)^6`

`=x^6+12x^5` `+60x^4+160x^3+240x^2` `+192x+64`

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