By inspection, we can see that: `a = 2`, `b = -7` and `c = -5`.

Substituting these into the quadratic formula, we get :

`x=(-b+-sqrt(b^2-4ac))/(2a)`

`=(-(-7)+-sqrt((-7)^2-4(2)(-5)))/(2(2))`

`=(7+-sqrt(49+40))/4`

`=(7+-sqrt(89))/4`

`=(7-sqrt89)/4 or (7+sqrt89)/4`

`=-0.6085 or 4.108`

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