Here, `a^2= 100`, so `a = ± 10`, so the vertices are at `(-10, 0)` and `(10, 0)`.

Now

`c=sqrt(a^2-b^2)`

`=sqrt(100-64)`

`=sqrt36`

`=6`

So the foci are at `(-6, 0)` and `(6, 0)`.

246810-2-4-6-8-10246810-2-4-6-8-10xyVerticesFociOpen image in a new page

Ellipse showing vertices and foci.

Please support IntMath!