Here, x_{1} = 3 and y_{1} = −4; x_{2} = 5 and y_{2} = 7

So the distance is given by:

`d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)` `=sqrt((5-3)^2+(7-(-4))^2)` `=sqrt(4+121)` `=11.18`

`d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

`=sqrt((5-3)^2+(7-(-4))^2)`

`=sqrt(4+121)`

`=11.18`

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