First we determine the values we will need for Cramer's Rule:

a1 = 1 b1 = −3 c1 = 6

a2 = 2 b2 = 3 c2 = 3

`x=|(6,-3),(3,3)|/|(1,-3),(2,3)|=(18+9)/(3+6)=3`

`y=|(1,6),(2,3)|/|(1,-3),(2,3)|=(3-12)/(3+6)=(-9)/9` `=-1`

So the solution is `(3, -1)`.

Check:

[1] `3 + 3 = 6` OK

[2] `6 - 3 = 3` OK

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